Some very useful Trigonometry formulas and Identities with proof are given here. Here we would also discuss some of the very important practical applications of these formulas in real life with examples.
Sine Formula
Let, In a △ABC, the length of sides: BC=a, CA=b, and AB=c then according to the Sine Formula
\frac{a}{Sin(A)}=\frac{b}{Sin(B)}=\frac{c}{Sin(C)}=2R.
Here R is the Circumradius of the △ABC.
Here is the proof of this formula.
Draw AD⟂BC, the height AD=h
In △BDA, Sin(B)=\frac{h}{c}.
h=c.Sin(B)
Similarly, In △CDA
Sin(C)=\frac{h}{b}.
h=b.Sin(C)
So, c.Sin(B)=b.Sin(C)
\frac{b}{Sin(B)}=\frac{c}{Sin(C)} ……………(i)
Now, Draw BE⟂AC, the height BE=k
\frac{a}{Sin(A)}=\frac{c}{Sin(C)} ……………(ii)
From the equation (i) and (ii):
\frac{a}{Sin(A)}=\frac{b}{Sin(b)}=\frac{c}{Sin(C)} ……………(iii)
Draw a Circumcircle of △ABC. Here O is the Circumcenter of the triangle.
The length of Circumradius=R
So, the length of the diameter, BD=2R
∠BAC=∠BDC=∠A (Angles, subtended by the same arc at the circumference in the same segment)
∠BCD=90° (Angle made by the diameter at the Circumference)
Now in △BCD, according to Sine Rule:
\frac{BC}{Sin(BDC)}=\frac{BD}{Sin(90°)}.
\frac{a}{Sin(A)}=\frac{2R}{1}.
\frac{a}{Sin(A)}=2R …………(iv)
From equation (iii) and (iv):
\frac{a}{Sin(A)}=\frac{b}{Sin(B)}=\frac{c}{Sin(C)}=2R.
Cosine Formula
Let, In an △ABC, the length of sides: BC=a, CA=b, and AB=c. BD is perpendicular drawn from vertex B to side AC, here h is the height of the triangle.
Then, According to Cosine Formula:
a2=b2+c2-2bc×Cos(A)
b2=c2+a2-2ac×Cos(B)
c2=a2+b2-2ab×Cos(C)
Here is the proof of this formula.
Apply Pythagoras Theorem in △BDC
a2=h2+DC2
R.H.S.
=h2+(AC-AD)2
=h2+AC2+AD2-2.AC.AD
=(h2+AD2)+b2-2.b.AD
=c2+b2-2.b.AD
Note: h2+AD2=c2 (Pythagoras Theorem)
Note: In △ADB
Cos(A)=\frac{AD}{AB}=\frac{AD}{c}.
AD=c.Cos(A)
So, a2=b2+c2-2.bc.Cos(A)
Similarly, we can prove other combinations also.
In △ADB, Cos(A)=\frac{AD}{c}.
AD=c.Cos(A) ………(i)
In △CDB, Cos(C)=\frac{CD}{a}.
CD=a.Cos(C) ………(ii)
Add both equations:
AD+CD=c.Cos(A)+a.Cos(C)
AC=c.Cos(A)+a.Cos(C)
b=c.Cos(A)+a.Cos(C) ……… (iii)
Similarly, we can prove:
a=b.Cos(C)+c.Cos(B) ……… (iv)
c=a.Cos(B)+b.Cos(A) ……… (v)
The Stewart’s and the Apollonius’s Theorem Proof: Click Here
More Trigonometry Formulas and Concepts are coming soon…
